\[ R'(x) = \frac{d}{dx}[\ln(x^2 + 4x + 5)] = \frac{2x + 4}{x^2 + 4x + 5} \]

\[ R'(x) = \frac{d}{dx}[\ln(x^2 + 4x + 5)] = \frac{2x + 4}{x^2 + 4x + 5} \]

Related Articles

Trending Articles

The Amarin Hack That Everyones Using—See How It Transformed My LifeAmazon Stock Price Skyrockets in April 2025—Watch the Billion-Dollar Surge Arc!#4 Mystery Behind Amazons Amazing Stock Price Jump This April 2025!Amazon Stock Price Hits All-Time High in April 2025—What Drives This Wild Move?Investors Panic and Celebrate: Amazons April 2025 Stock Price Explosion!April 2025: Amazons Stock Price Soars—Heres Why You Cant Ignore It!Amarin Pharma Stock Soars—Is It the Next Industry Game-Changer?!Shocked You Miss This? Amarin Pharma Stock Explodes After Breakthrough Drug!Investors Got Reactionary: Amarin Pharma Stock Hits All-Time High Today!Is Amarin Pharma Stock a Hidden Golden Opportunity? Dont Miss Out!