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/ & 0 & 1
& 0 & 1
February 22, 2026
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\begin{bmatrix}
& 0 & 0 \\
& 1 & 0 \\
\end{bmatrix}
The determinant of this matrix is \(1\). Therefore, the volume is:
V = \frac{1}{6} \times |1| = \frac{1}{6}
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