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/ \( 145 = 5 (10 + 9d) \)
\( 145 = 5 (10 + 9d) \)
February 22, 2026
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Sum formula: \( S_n = \frac{n}{2} (2a + (n-1)d) \)
Here, \( S_{10} = 145 \), \( a = 5 \), \( n = 10 \)
\( 145 = \frac{10}{2} (2 \times 5 + 9d) \)
\( 145 = 50 + 45d \)
\( 95 = 45d \)
\( d = \frac{95}{45} = \frac{19}{9} \approx 2.11 \)
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