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So \( x = 1 \) and \( x = 3 \) are critical points.
Check \( f(1) = 2 \):
f(1) = 1^3 - 6(1)^2 + 9(1) + c = 1 - 6 + 9 + c = 4 + c
+ c = 2 \Rightarrow c = -2
#### #### -2
Find the radius of a circle if the circumference is equal to the area.
Solution 9:
Let the radius be \( r \).
Circumference = \( 2\pi r \), Area = \( \pi r^2 \).
Equating: