Home / Minimum length for 3 non-adjacent G’s: G _ G _ G → 5 positions. Only one such configuration up to shift: G G G with gaps — actually, only possible if they are in positions with separation.

Minimum length for 3 non-adjacent G’s: G _ G _ G → 5 positions. Only one such configuration up to shift: G G G with gaps — actually, only possible if they are in positions with separation.

February 22, 2026

Try: placing 3 G’s with no two adjacent in 5 positions.
Let the G’s occupy 3 positions such that no two are adjacent.
Then gaps: between G’s must be at least one non-G.
Positions: must satisfy $ g_2 \ge g_1 + 2 $, $ g_3 \ge g_2 + 2 $. The minimal span is 5: e.g., 1,3,5.
Only one such triplet of positions in 8? No — multiple.
But we already fixed C’s, and the 5 free positions are a subset of the 8, not consecutive.