\( w = \sqrt{64} = 8 \).

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• Area = length \(\times\) width = \( 3w \times w = 3w^2 \).
• Given \( 3w^2 = 192 \).
• Solving for \( w \): \( w^2 = \frac{192}{3} = 64 \).
• A certain number is increased by 25% to become 125. What was the original number?
• Increasing \( x \) by 25% gives \( x + 0.25x = 1.25x \).
• Given \( 1.25x = 125 \).

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